tentukan panjang CE!
Penyelesaian :
AD = 3 cm
DB = 2 cm
AE = 6 cm
EC = x
[tex] \sf \frac{ad}{db} = \frac{ae}{ec} [/tex]
[tex] \sf \: \frac{3}{2} = \frac{6}{x} [/tex]
[tex] \sf \: 3.x = 2.6[/tex]
[tex] \sf \: 3x = 12[/tex]
[tex] \sf \: x = \frac{12}{3} [/tex]
[tex] \sf \: x = 4 \: cm[/tex]
[tex] \frac{DA}{BD} = \frac{EA}{CE} [/tex]
[tex] \frac{3}{2} = \frac{6}{CE} [/tex]
[tex]3(CE) = 2(6)[/tex]
[tex]3CE = 12[/tex]
[tex]CE = \frac{12}{3} [/tex]
[tex]CE = 4 \: cm[/tex]
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